Question

The number are in the ratio 1:2:3 the sum of their cube is 62208 find the numbers?

Answer 1

Step-by-step explanation:

➡️let the common multiple be x

(x + 2x + 3x )^3 = 62208

USE ABOVE CONDITION TO SOLVE IT..

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Answer 2

Answer:

Step-by-step explanation:

Lets take the numbers as 1x 2x and 3x

(1x)^3+(2x)^3+(3x)^3= 62208

(6x)^3= 62208

36x^3= 62208

x^3= 62208/36

x^3= 1728

Therefore

x= cube root of 1728

x=12

the numbers are:

1x= 1×12=12

2x=2×12=24

3x=3×12=36

To check whether it is correct

12^3+24^3+36^3=62208

1728+ 13824+ 46656=62208

62208=62208

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