Math, asked by Vaishnavi4091, 1 year ago

The number obtained by interchanging the digits of a two-digit number is less than the original number by 63. if the sum of the digits of the number is 11, what is the original number?

Answers

Answered by Anonymous
1
heya dear

your answer is in the attachment .

-------------------------------------------------------------------------------------------------------- now the number is 10y+x

= 10×9 + 2

= 90 + 2

= 92


i hope it helps u
Attachments:
Answered by jhangir789
0

The original number is, 92.

Definition of digit?

  • A digit is a written symbol for any of the ten numbers from 0 to 9.
  • Her telephone number differs from mine by one digit.
  • Synonyms: number, figure, numeral, integer More Synonyms of digit.

According to the question:

Let the unit digit is $\mathrm{x}$ and tens digit is $\mathrm{y}$ of a two digits number, original number is (10 y+x). The number by interchanging the digits is (10 x+y), accordingly :-

(10 y+x)-(10 x+y)=63 .

or,9y-9 x=63

or,y-x=7 (1), and y+x=11. (2).

Adding eqn.(1) & (2).

2y=18

=>y=18 / 2

=9

Putting y=9 in eqn.(2) ,

9+x=11, or, x=11-9=2.

Thus, the original number =10 y+x=10 \times 9+2=92$. Answer.

Hence, 92 is the original number.

#SPJ2

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