Math, asked by vaishalipandey190951, 1 year ago

The number of 6 digit numbers of the form "ABCABC", which are divisible by 13. where A. B
and C are distinct digits. A and C being even digits is
A) 200
B) 250
C) 160
D) 128

Answers

Answered by CUTESTAR11
4

Step-by-step explanation:

I think option B)is the answer..

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Answered by Anonymous
9

Your question

The number of 6 digit numbers of the form "ABCABC", which are divisible by 13. where A. B

The number of 6 digit numbers of the form "ABCABC", which are divisible by 13. where A. Band C are distinct digits. A and C being even digits is ?

Hii

you are welcome in my answer

clue given

ABCABC is divisible by 13

take

1️⃣option 1

200200 it is divisible by 13 ✔️

but B and C are same so it is not

2️⃣option 2

250250 divisible by 13✔️

All three number are distinct ✔️

but c is not even so it's wrong

3️⃣Option C

160160 is divisible by 13 ✔️

all three are distinct number ✔️

A place contain odd number so it is also not

4️⃣Option D ✔️

128128 it is divisible by 13 ✔️

all three are distinct ✔️

A and c place have Even digit ✔️

so option D is right number is 128128

where

ABC = 128✔️✔️

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