Question

the number of atoms in 0.1 mol of a tetraatomic gas is (NA =6.022×10^23 mol^_1)

Answer 1

SALUT AMIS !!



Given ,

Atomicity of Molecule = 4

Avogardo Number. = 6.022 × 10 ^23

=|| 0.1 molecule gas.

Number of atoms. = Mole × Avagardo number " x "

Atomicity of Molecule = 0.1 × 6.022 × 10 ^ 23 × 4

= 2.40 × 10 ^ 28 atoms

No. of atoms in a 0.1 mole of tetra atomic gas = 2.40 × 10^28



HOpe IT heLPs !!

Answer 2

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→Tetra -atomic gas , it means in one molecule of gas equal 4 atoms of gas.

hence,

→No of mole of atoms = 4 × no of mole of molecule

→No of mole of atoms = 4 × 0.1 = 0.4

→No of atoms = no of mole × NA

→No of atoms = 0.4 × 6.023 × 10²³

→No of atoms = 2.4092 × 10²³