The number of atoms in 0.5 mole of Al2(CO3)3
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the relative molecular mass of AL2(CO3)3=
27×2+(12+16×3)3=54+(12+48)3=234g.
then 1 mole of AL2(CO3)3 contains =234g=6.022×10²⁴atoms.
then the no. of atoms in the given compound=
3.011×10²³ atoms.
then, no. of atoms in oxygen=144/234×6.022×
10²³=3.075×10²³ atoms.
27×2+(12+16×3)3=54+(12+48)3=234g.
then 1 mole of AL2(CO3)3 contains =234g=6.022×10²⁴atoms.
then the no. of atoms in the given compound=
3.011×10²³ atoms.
then, no. of atoms in oxygen=144/234×6.022×
10²³=3.075×10²³ atoms.
Osama11:
em asking number of atoms of oxygen
oooo
sorry
u have not mentioned
sorry my mistake :-P
ok tell me the number of atoms of oxygen in this
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