Question

The number of atoms in 20 g of So3 is approximately​

Answer 1

Answer:

Each moleucle of SO3 has 4 atoms. Moles present in 20 g of SO3 = 20/ 80.07 = 0.2498 mol. Number of molecules = 0.2498 X 6.022 X 1023 = 1.5 X 1023 molecules. Each mole of SO3 has 6.022 X 1023 molecules..

Answer 2

Answer:

2.509x10^23

Explanation:

gram atoms

48 6.022x10^23

20 a

a=6.022x10^23x20/48