Question

The number of atoms in 4.25 g of NH3 is approximately?

Answer 1

17g ammonia contains 6.022×10^23 number of ammonia molecules. So 4.25 g ammonia will contain (6.022×10^23×4.25)/17 = 1.5×10^23 number of ammonia molecules. Each molecule contain 4atoms (1 N atom and 3 H atoms). ... 17gram of NH3 containsmolecules=6.022×10^23.

Answer 2

$\Huge\purple{\mathfrak{\underline{\underline{Solution}}}}$

→ Molar mass NH3 = 14+3 = 17g/mol

→ 4.25g = 4.25/17 = 0.25 mol NH3

→ 1mol = 6.022× 10²³ molecules

→ 0.25 mol = 0.25×6.022×10²³

→ Number of molecules = 1.51×10²³ molecules NH3.