The number of atoms in an element equal to 1 mole of any element is equal to the Avogredo number. Which of the following element?
Will have the maximum number of atoms?
(A) 4 g He
(1) 46 g Na
(c) 0.40 g Ca.
(D) 12 g He
Answers
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0
Answer:
D) 12g Ca
Explanation:
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Answer:
iv) 12g He
Explanation:
12g He contains more no.of atoms.
No.of moles = No.of given atoms/avagadro
no.of atoms
No.of atoms = No.of moles × avagadro no.
(i) no.of atoms = 4g/4g × No = 1No
(ii) no.of atoms = 46g/23g × No = 2× No
(iii) no.of atoms = 0.40/40 ×No = 0.1 ×No
(iv) no.of atoms = 12g/4g × No = 3×No
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