Question

The number of atoms present in 4.25 grams of nh3 is approximately

Answer 1

Answer:

and is nA(avogadro no. are present)

Explanation:

no. of atoms =moles x nA x 4

4.25/17 x nA x4= nA

Answer 2

Explanation:

4.25÷17=0.25 mol×6.022×10^23= 1.51×10^23 atoms/ molecules