Question

the number of common solutions for the system of linear equations 5x +4y +6 =0 and 10x +8y =12 is ​

Answer 1

Answer:

There is no unique solution

Answer 2

The equation has no solution

Solution:

Given that.

5x + 4y + 6 = 0

10x + 8y = 12

Rewrite the equations

5x + 4y = -6 -------- eqn 1

10x + 8y = 12 ------- eqn 2

Multiply eqn 1 by 2

10x + 8y = -12 -------- eqn 3

Subtract eqn 3 from eqn 2

10x + 8y = 12

10x + 8y = -12

( - ) ---------------------------

0 = 12 + 12

$0\neq 24$

Thus the equation has no solution

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