Question

The number of electrons in the outermost shell of alkali metals is......

Answer 1

Answer:  

The number of ‘electrons’ in the ‘outermost shell’ of alkali metals is 1.

Explanation:

The alkali metals which are found in group 1 of the ‘periodic table’ are -

• Sodium (Na)
• Rubidium (Rb)
• Francium (Fr)
• Potassium (K)
• Cesium (Cs)
• Lithium (Li)  

These ‘alkali metals’ are very reactive in nature. They do not occur freely. All these characteristics and experiments show that only 1 electron found in the outermost shell of alkali metals. Therefore they are ‘highly reactive’ for reaction by losing their 1 electron of the outer shell.

Answer 2

The number of electrons in the outermost shell of alkali metals is one.

Explanation:

• Chemical elements lithium (Li), sodium (Na), potassium (K),rubidium (Rb), caesium (Cs),and francium (Fr) are collectively called Alkali metals.
• They have one electron present in their valence shell.
• The electronic configuration of alkali metal is given by $ns1$
• General electronic configuration is $(n-1)s2p6d10ns1$
• They are generally very reactive in nature as they do not occur freely in nature.
• They have only one electron in the outermost shell of the alkali metals.
• The characteristics of alkali metals are that they all  are shiny, soft, highly reactive metals at standard temperature and pressure.
• They lose their outermost electron very readily in order  to form cations with charge +1.
• These elements can all be cut easily with a knife due to their softness.
• Alkali metals are also known as the lithium family after its leading element.
• IUPAC group number of alkali metal is 1

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