Question

the number of electrons present in 53 g of Na2CO3?

Answer 1

Molar mass of Na2CO3​ = 106 gmol-1

No. of moles = Given mass Molar mass= 53106 = 0.5 mol
​No. of electrons in 1 molecule  = 2×10 (Na+) + [6+(8×3)+2 ](CO32−)  
                                                                    = 20+ 32 = 52 electrons
No. of electrons in 1 mole = 52×6.022×1023
                                                             = 3.13×1025
No. of electrons in 0.5 mol = ​3.13×1025×0.5 = 1.56×1025 

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