Question

The number of gram atoms of oxygen present in 1.28g of SO2 IS

Answer 1

SO2 Is Sulfur Oxide

Sulfur has atomic mass 32

Oxygen has 16

There are 2 Atoms of Oxygen..

So,16×2=32

Now Total Molar Mass of SO2 = 32+32=64

Moles = Given mass / molar mass

= 1.28 / 64

= 0.02 Moles

Now, Oxygen has 2 Atoms...

So,0.02×2 = 0.04

Your Answer is B) 0.04

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Answer 2

Answer:

Molar mass of SO2 = 32 + 2×16 = 64

moles = gn mass / molar mass

= 1.28/64 =0.02

No.of oxygen atom = 0.02 × 2 = 0.04

Ans = 0.04

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