Question

The number of hydrogen atoms present in 17 g of ammonia

Answer 1

Moles of ammonia
$= \frac{given \: mass}{molar \: mass} = \frac{17}{17} = 1 \\ hence \: no \: of \: hydrogen \: atoms \\ = atomicity \: of \: h \times mole \times avagoadro \\ = 3 \times 1 \times 6.022 \times {10}^{23} \\ = 18.066 \times {10}^{23}$