Question

the number of molecules present in 4.25gm of ammonia is

Answer 1

So 17g ammonia contains 6.022×10^23 number of ammonia molecules. So 4.25 g ammonia will contain (6.022×10^23×4.25)/17 = 1.5×10^23 number of ammonia molecules. Each molecule contain 4 atoms (1 N atom and 3 H atoms).

please mark as brainlies im trying to level up