Chemistry, asked by sukrititom, 1 year ago

THE NUMBER OF MOLES OF KMnO4 OF KMnO4 REDUCED BY 1 MOLE OF KI IN ALKALINE MEDIUM IS
1] ONE
2] 2
3]5
4] 1/5

Answers

Answered by dimpy7
213
Hi friend ...

The correct option is 2) two.
The reaction is as follows :
KI + 2KMnO4 + H2O gives KIO3 + 2 KOH + MnO2

Hope u got...


sukrititom: DID YOU BALANCED IT BY ALKALINE MEDIUM ELECTRON METHOD OR YOU KNOW SOME SHORT TRICK,PLZ SHARE IF YOU KNOW IT WILL BE A GREAT HELP FOR ME :)
Answered by mindfulmaisel
60

"The number of moles of KMn{ O }_{ 4 } is reduced by one mole of KI in presence of alkaline medium is 2] 2 moles.

"Alkaline solution" is a "base and water" mixture and the solution shows the mid-point (7) in pH scale.

In presence of alkaline medium KMn{ O }_{ 4 } react with KI to form potassium iodate, potassium hydroxide, and manganese dioxide.

The chemical reaction is as follows,

KI\quad +\quad 2KMn{ O }_{ 4 }\quad +\quad { H }_{ 2 }O\quad \rightarrow \quad KI{ O }_{ 3 }\quad +\quad 2KOH\quad +\quad Mn{ O }_{ 2 }"

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