Question

the number of moles present in 24.5g of H2SO4

Answer 1

molecular mass of H₂SO₄ = 2*1+16*2+32*4 = 98

THEREFORE,

98 gm H₂SO₄ = 1 mole H₂SO₄

1 gm H₂SO₄ = 1/98 mole H₂SO₄

24.5 gm H₂SO₄ = 24.5/98 = 0.25 mole H₂SO₄

Answer 2

Answer: The number of moles of $H_2SO_4$ will be 0.25 moles.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

We are given:

Given mass of sulfuric acid = 24.5 g

Molar mass of sulfuric acid = 98 g/mol

Putting values in above equation, we get:

$\text{Moles of }H_2SO_4=\frac{24.5g}{98g/mol}\\\\\text{Moles of }H_2SO_4=0.25mol$

Hence, the number of moles of $H_2SO_4$ will be 0.25 moles.