Question

the number of nitrogen molecules present in 1 c.c of gas at NTP is

i want with propeer explanation

Answer 1

1 m³ = 1000 L
1000 cc = 1 L
1 cc = 10⁻³ L

so 22.4 L N₂ has 6.022 x 10²³ molecules

1 L N₂ has $\frac{6.022*10^{23}}{22.4}$ molecules

10⁻³ N₂ has $\frac{6.022*10^{23}*10^{-3}}{22.4}$ molecules

10⁻³ N₂ has $2.68*10^{19}$ molecules

Answer 2

22.4 litres of nitrogen gas consists = 6.023 *10^23 molecules We know that 1 liter = 1000ml=1000 c.c Hence, 1 c.c will contain molecules = 6.023 *10^23/ 22.4 *1000 = 2.68 * 10^19 molecules