Question

the number of primes from the series(2019!+2)(2019!+3)(2019!+4)....(2019!+2019)​

Answer 1

Answer:

no prime number

Step-by-step explanation:

The number of primes from the series(2019!+2)(2019!+3)(2019!+4)....(2019!+2019)​

There will be no prime numbers

2019! = 2019 * 2018 * 2017 *.............................................3*2 *1

2019! + 2 = (2019 * 2018 * 2017 *.............................................3*2 *1 )  + 2

= 2((2019 * 2018 * 2017 *.............................................3*1*1 )  + 1 )

2019! + 3 = (2019 * 2018 * 2017 *.............................................3*2 *1 )  + 3

= 3((2019 * 2018 * 2017 *.............................................1*2 *1 )  + 1 )

2019! + 4 = (2019 * 2018 * 2017 *.............................................3*2 *1 )  + 4

= 4((2019 * 2018 * 2017 *.............................................1*3*2 *1 )  + 1 )

2019! + 2018 = (2019 * 2018 * 2017 *.............................................3*2 *1 )  + 2018

= 2018((2019 *1 * 2017 *.............................................3*2 *1 )  + 1 )

2019! + 2018 = (2019 * 2018 * 2017 *.............................................3*2 *1 )  + 2018

= 2018((1*2018* 2017 *.............................................3*2 *1 )  + 1 )

so no prime number