Physics, asked by SoumyaDutta4074, 10 months ago

The number of significant figures in 0.06900 is(a) 5 (b) 4(c) 2 (d) 3


vhpsharitha: that's 3

Answers

Answered by vv14062003
4

(b)4 is the answer of your ques.

Answered by Anonymous
2

Answer:

B) 4

Explanation:

The significant figures of a number are the ones that add the valuable importance to the respective number. The suffixing and prefixing of zeros in decimal number and normal number value also has a significant figure value.

Therefore, the given number is a decimal number having zero in the front as well as at the last. The zero in front lets the decimal attain a value, whereas the zero in the last is just a digit without major importance. Therefore, the number of significant figures in 0.06900 is 4 because of actual valuable number to be 0.069.

Similar questions