Question

the number of ways in which the letter of word ARGUMENT can be arranged so that only consonants occur at both ends is:

Answer 1

☆☆☆☆hii mate☆☆☆☆
HERE IS YOUR ANSWER ⤴ ⤴ ⤴ ⤴
may it help you

Answer 2

The number of ways in which the letter of word ARGUMENT can be arranged so that only consonants occur at both ends is:

Explanation:

the number of consonants and vowels of the given word are

Vowels – A, U, E = 3

Consonants – R, G, M, N, T = 5

On solving C(5,2) we get solution as 10

This provide us the total number of arrangements

10×2=20

Now we have to select 2 consonants out of 5 –

C(5,2) So we will write the formula of combination and substitute values to solve

⇒6!=6×5×4×3×2×1=720

With this the total number of ways in which the words can be arranged is

10×2×720=14400

Answer = 14400