Question

The numbers which exceed their square root by 12 is

Answer 1

let the  number be x 

according to question 

√x + 12 = x 

⇒√x= x - 12

squaring both sides

⇒x= x² - 24x +144

⇒x² - 25x + 144 = 0 

⇒x² - 16x - 9x +144=0

⇒x(x - 16) - 9(x - 16)=0

⇒(x - 9)(x - 16)=0

so the number is 9,16

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