Question

The numerator of a fraction is four less than the denominator if one is added to the numerator and two Substract it from the denominator of the fraction becomes 9 x 8 find the origin of fraction

Answer 1

let the numerator and denominator be "x"
N/D=
$(x - 4) + 1 \div x - 2 = 9 \div 8 \\ 8(x - 4) + 1 = 9(x - 2) \\ 8x - 32 + 1 = 9x - 18 \\ 8x - 9x = 13 \\ x = - 13 \\ now \: putting \: the \: value \: of \: \\ x = \\ \\ x - 4 \div x - 2 \\ - 13 - 4 \div - 13 - 2 \\ \\ 17 \div 13$