Question

the numerator of the fraction is 4less than its denominator if 2 is added to both the numerator and denominator the fraction becomes 5 by 7 find the fraction?

pls friends answer this i am help​

Answer 1

$\huge\bf\red{\underline{\green{Answer}}}$

Let the numerator and denominator of a fraction be x and y

We are given that

y -x = 4

y + 1 = 8(x-2)

Then, the equation formed are

y x = 4.......(1)

y + 1 = 8(x 2).......(2)

To solve equation we put y = x+4 in eq(2)

(x+4) +1 = 8x -16

7x = 21

x = 21/7 =3

Putting x =3 in equation(1) we get

y =7

On solving equation (1) and (2) we get

x = 3 and y = 7

Hence, fraction is

7

3

Answer 2

$\huge \frak \pink{Hello}$

Question:-

the numerator of the fraction is 4 less than its denominator if 2 is added to both the numerator and denominator the fraction becomes 5 by 7 find the fraction?

Answer:-

let us assume the denominator be X

hence, numerator becomes x-4

now according to the question :-

we will get this equation ⬇️

$\frac{x - 4 + 2}{x + 2} = \frac{5}{7}$

By simplifying:-

$\frac{x - 2}{x + 2} = \frac{5}{7} \\ ⇒7(x - 2) = 5(x + 2) \\ ⇒7x - 14 = 5x + 10 \\ ⇒2x = 24 \\ ⇒x = 12$

⇒Denominator = X = 12

⇒Numerator = x-4 = 12-4 = 8

hence the fraction becomes ⬇️

$\frac{8}{12} = \frac{4}{3}$

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Hope it helps ⭐⭐⭐