Question

the object travell 32 m in 8 sec the another 32in 4 ec what is average speecd of the object​

Answer 1

6m/s is the answer bcz speed=distance÷time

therefore in first case speed=32÷8=4m/s

in second case speed=32÷4=8m/s

hence,average speed=speed of two object÷no.of object

i.e. 4+8÷2=6m/s

therefore average speed is 6 m/s