The ones digit , tens digit and hundreds digit of a 3-digit number are in the ratio 4:3:2 . If the difference of this number and the number obtained on reversing the digits is 396 , find the original 3-digit number .
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Answer: 468
Step-by-step explanation:
Let the ones digit be 4a, tens digit be 3a and ones digit be 2a
then the number is 2a×100 + 3a×10 + 4a = 200a+30a+4a=234a
The reverse number is 4a×100 + 3a×10 + 2a=400a+30a+2a=432a
The difference is 396
So 432a-234a=396
198a=398
a=2
so the number is 468
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