Question

the ones digits of two digits number is twice the tens digit when the number formed by reversing the digit is added to the original number the sum is 99 find the original number​

Answer 1

Answer:

36

Step-by-step explanation:

Let, the tens digit =x

so, ones digit =2x

.•. number= 10x+2x=12x

reverse number= 10×2x+x=20x+x=21x

it is given that,

12x+21x=99

or 33x=99

so, x=3

original number=10x+2x

=30+6

=36 

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Answer 2

Answer:

Let the tens digit be y and the ones digit be x.

The original number = 10y + x

The reverse number = 10x + y

It is given that ones digit is twice the tens digit :]

➳ x = 2y ............[Equation (i)]

According to question now,

➳ 10x + y + 10y + x = 99

➳ 11x + 11y = 99

➳ 11 (x + y) = 99

➳ x + y = 99/11

➳ x + y = 9

➳ y = 9 - x.........[Equation (ii)]

Now, Substituting equation (ii) in equation (i) we get :

➳ x = 2 (9 - x)

➳ x = 18 - 2x

➳ 3x = 18

➳ x = 18/3

➳ x = 6

Putting x = 6 in equation (ii) we get :

➳ y = 9 - x

➳ y = 9 - 6

➳ y = 3

Therefore,

The original number = 10y + x = 10(3) + 6 = 30 + 6 = 36