The ones of a 2disits Number is twice the tens disits. When the number formed by reversing the disits is added to the original number the sum find 99.find the original number?
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Answered by
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y=3 and x= 6 and original no is 36
kiNgShaurya:
answer is 63 not 36
Answered by
1
let the ones digit be 2x
thens digit = x
orignal no. =10(x) + 2x = 12x
on reversing the no.s we get =10(2x) + x=21x
therefore,
21x + 12x =99
33x = 99
x = 99/33 = 3
orignal no. = 12x = 12x3 = 36
thank you, plz mark as brainliest.
thens digit = x
orignal no. =10(x) + 2x = 12x
on reversing the no.s we get =10(2x) + x=21x
therefore,
21x + 12x =99
33x = 99
x = 99/33 = 3
orignal no. = 12x = 12x3 = 36
thank you, plz mark as brainliest.
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