Question

The orbital angular momentum of an electron in 2s orbital is
0.5hπ
0
h/2π
√2h/π

Answer 1

Answer: 0

Explanation:

The orbital angular momentum of an electron is given by:

$\sqrt{l(l+1)}\frac{h}{2\pi}$

l = azimuthal quantum number

h = plank's constant

Principle Quantum Numbers : It describes the size of the orbital and the energy level. It is represented by n. Where, n = 1,2,3,4....

Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

For 2 s

n=2  and l = 0

Thus ${\sqrt{0(0+1)}\frac{h}{2\pi}=0$