Math, asked by PragyaTbia, 11 months ago

The order of the differential equation 2x^2 \frac{d^2y}{dx^2} -3 \frac{dy}{dx} +y =0 is
(A) 2
(B) 1
(C) 0
(D) not defined

Answers

Answered by hukam0685
0
Answer: 

Order=2

Degree=1

Solution:

Order of differential equation: Order is the highest numbered derivative in the equation.

Degree of differential equation: Degree is the highest power to which highest numbered derivative is raised when equation is free from radicals.

2x^2 \frac{d^2y}{dx^2} -3 \frac{dy}{dx} +y =0

here highest numbered derivative is 2

So, order is 2

That highest number derivative raised to power 1

So, it's Degree is 1

Option A is correct.
Hope it helps you.

Similar questions