The owner of a small restaurant can prepare a particular meal at a cost of Rupees 100. He estimates that if the menu price of the meal is x rupees, then the number of customers who will order that meal at that price in an evening is given by the function D(x) = 200−x. Express his day revenue, total cost and profit on this meal as functions of x. 3
Answers
Cost of metal =Rs in 100
Total cost =Rs 100(200-x)
Number of costumer =(200-x) x
Day revanue =(200-x) x
Total profit = Day revenue - Total cost
=(200-x)x-(100)(200-x)
Given : a particular meal cost Rs 100
if the menu price of the meal is x rupees, then the number of customers who will order that meal at that price in an evening is given by the function D(x) = 200−x
To Find : his day revenue
Total cost
profit
Solution:
Cost per meal = 100 Rs
Price for a meal = x Rs
Demand of meals = 200 - x
Revenue = Demand * Price
= (200 - x) x
=> R(x) = 200x - x²
his day revenue 200x - x²
Total cost = 100 (200 - x)
= 20000 - 100x
total cost = 20000 - 100x
Profit = Revenue - Total cost
Profit = 200x - x² - (20000 - 100x)
=> Profit = 300x - x² - 20000
P(x) = -x² + 300x - 20000
Profit = -x² + 300x - 20000
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