the paper of in the form of a rectangle d a r k in which d a = 30 cm and Kd is = 21 CM or semicircular portion of a AR as diameter is cut off. find the area of the remaining part.
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remaining area = area of rectangle - area of semi circle.
A = l×b - πr^2/2= 456.75cm^2.
A = l×b - πr^2/2= 456.75cm^2.
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Answer:
The area of the remaining part is 456.75cm² .
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