Math, asked by manjeet1127, 1 year ago

the parallel sides of a trapezium are 26 cm and 30 cm. the altitude to the base 30 cm is 21 cm. find the area of the trapezium

sumbul100: parallel sides:
a = 26cm
b = 30cm

distance between parallel sides, h = 21cm

Areaoftrapezium=12(a+b)hArea=12×(26+30)×21Area=12×56×21Area=588cm2\begin{lgathered}Area \: of \: trapezium = \frac{1}{2} ( a + b)h \\ \\ Area = \frac{1}{2} \times (26 + 30) \times 21 \\ \\ Area = \frac{1}{2} \times 56 \times 21 \\ \\ Area = 588 \: cm {}^{2}\end{lgathered}Areaoftrapezium=21(a+b)hArea=21×(26+30)×21Area=21×56×21Area=588cm2

Answers

Answered by TPS

parallel sides:
a = 26cm
b = 30cm

distance between parallel sides, h = 21cm

$Area \: of \: trapezium = \frac{1}{2} ( a + b)h \\ \\ Area = \frac{1}{2} \times (26 + 30) \times 21 \\ \\ Area = \frac{1}{2} \times 56 \times 21 \\ \\ Area = 588 \: cm {}^{2}$

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