the parallelogram and Rhombus are equal in area the diagonals of the Rhombus are 110 M and 44 M respectively if one of the side of the parallelogram is 88 M find its corresponding altitude
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given areas are equal so
1/2*110*44=88*x
so solving this --> 2420=88x
then x=27.5
1/2*110*44=88*x
so solving this --> 2420=88x
then x=27.5
Answered by
51
Hiii!!!
Here's Ur answer...
ATQ, area of rhombus = area of parallelogram
Given diagonals of the rhombus are 110m and 44m.
Area of the rhombus = 1/2 × d1 × d2
= 1/2 × 110 × 44
= 55 × 44
= 2420m²
Therefore area of parallelogram is also 2420m²
Base(side) of the parallelogram is given 88m.
Therefore b × h = 2420m²
==> 88 × h = 2420m²
==> h = 2420/88
==> h = 27.5m
Hence, altitude of the parallelogram is 27.5m
Hope this helps..!!
Here's Ur answer...
ATQ, area of rhombus = area of parallelogram
Given diagonals of the rhombus are 110m and 44m.
Area of the rhombus = 1/2 × d1 × d2
= 1/2 × 110 × 44
= 55 × 44
= 2420m²
Therefore area of parallelogram is also 2420m²
Base(side) of the parallelogram is given 88m.
Therefore b × h = 2420m²
==> 88 × h = 2420m²
==> h = 2420/88
==> h = 27.5m
Hence, altitude of the parallelogram is 27.5m
Hope this helps..!!
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