Question

The percent yield for the following reaction carried out in carbon tetrachloride (CCI4) solution is 80%

Br2 + CI2



2BrCI

(a) How many moles of BrCI is formed from the reaction of 0.025 mol Br2 and 0.025 mol CI2?

(b) How many moles of Br2 is left unreacted?​

Answer 1

Answer:

Br2 is the right answer