The percent yield for the following reaction carried out in carbon tetrachloride (CCI4) solution is 80%
Br2 + CI2
2BrCI
(a) How many moles of BrCI is formed from the reaction of 0.025 mol Br2 and 0.025 mol CI2?
(b) How many moles of Br2 is left unreacted?
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Answer:
Br2 is the right answer
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