The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is:
A.0.4
B.0.42
C.0.44
D.0.46
Answers
Answered by
2
Answer: C) 44%
Explanation:
Let original length = x metres and original breadth = y metres.
Original area = xy sq.m
Increased length = 120100120100 and Increased breadth = 120100120100
New area = 120100x*120100y=3625xy m2120100x*120100y=3625xy m2
The difference between the Original area and New area is:
3625xy−xy3625xy-xy
1125xy1125xy Increase % =(1125xyxy/)*1001125xyxy*100= 44%
Explanation:
Let original length = x metres and original breadth = y metres.
Original area = xy sq.m
Increased length = 120100120100 and Increased breadth = 120100120100
New area = 120100x*120100y=3625xy m2120100x*120100y=3625xy m2
The difference between the Original area and New area is:
3625xy−xy3625xy-xy
1125xy1125xy Increase % =(1125xyxy/)*1001125xyxy*100= 44%
Answered by
4
Answer: C) 44%
Explanation:
Let original length = x metres and original breadth = y metres.
Original area = xy sq.m
Increased length = 120100120100 and Increased breadth = 120100120100
New area = 120100x*120100y=3625xy m2120100x*120100y=3625xy m2
The difference between the Original area and New area is:
3625xy−xy3625xy-xy
1125xy1125xy Increase % = (1125xyxy/)*1001125xyxy*100= 44%
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