Question

The perimeter of 2 no. Square are 60m &144m find the perimeter of another square equal in area to the sum of 1st 2 no.

Answer 1

hey friend..!! Here's your answer
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Perimeter of 3rd square = area of 1st square + Area of second square

Perimeter if 1st sq = 60 m
4a = 60
a = 15 m

Area of 1st square = 15 × 15
= 225cm^2

Perimeter of 2nd square = 144
4a = 144
a = 36cm

Area of 2nd square = 36 × 36
= 1296cm^2

Area of 3rd square = 225 + 1296=
1521 cm^2

Side of 3rd square,

a^2 = 1521
a = 39 cm

Perimeter of 3rd square = 39 × 4
= 156 cm

So that the perimeter of 3rd square is 156 cm
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#Hope its help you dear#
☺

Answer 2

Sides of first two squares = (60/4) & (144/4) respectively

Sides of first two squares = 15 & 36 respectively


Sum of area of first two squares = (15)²+(36)²

Area of another square = 225+1296

Side of another square = √1521=39


Perimeter of another square = 4×39=156 m



I hope this will help you

-by ABHAY