Question

the perimeter of a floor of a room is 18m .what is the area of four walls of the room ,if its height is 3m.

Answer 1

If the floor is in rectangular shape


Then your answer is,

Perimeter of rectangle =2(l+b)

18=2(l+b)

Then,

Area of four walls =2(l+b) *h

Area of four walls=18*3

Area of four walls =54m²

Answer 2

Answer:

area of four walls of the room is, 54 meter square

Step-by-step explanation:

Perimeter of rectangle is given by:

$P=2(l+w)$ where l is the length and w is the width of the ractnagle respectively.

As per the statement:

the perimeter of a floor of a room is 18 m

⇒$2(l+w)=18$                  ......[1]

Area of four walls of the room is given by:"

$A=2(l+w)\cdot h$

Here, h = 3 m

Substitute the given values of [1] and h we have;

$A=18\cdot 3 = 54 m^2$

Therefore, area of four walls of the room is, 54 meter square