Question

The perimeter of a photograph is 30 inches. The photograph is 6 inches wide. How long is it?

Answer 1

Step-by-step explanation:

perimeter = 30

width(breath) = 6

perimeter of rectangle = 2(l+b)

2(l+b) = 30

l+6=30/2

l+6=15

l=15-6

l=9

therefore length is 9 inches

Answer 2

$\bigstar$ Question:

The perimeter of a photograph is 30 inches. The photograph is 6 inches wide. How long is it?

$\bigstar$ Given:

• The perimeter of a photograph = 30 inches
• Width of the photograph = 6 inches

$\bigstar$ To Find:

• Length of the photograph.

$\bigstar$ Solution:

Given, perimeter of the photograph is 30 inches and the width of it is 6 inches.

Let l be the length of the photograph

$\boxed{\sf Perimeter = 2(l+b)}$

Perimeter of the photograph = $\sf 2(l+b)=30$

$\implies \sf 2(l+6)=30$

$\implies \sf l+6=\dfrac{30}{2}$

$\implies \sf l+6=15$

Now, finding the value of l

$\implies \sf l=15-6$

$\implies \sf{\underline{\underline{ Length =9 \: inches}}$

∴ The photograph is 9 inches long.

$\bigstar$ Points to Note:

➤ The formula to find the perimeter is $\sf 2(l+b)$

➤ The perimeter of a rectangle is the total length of all the sides of the rectangle.