The perimeter of a rectangle is 152 meters. The width is 22 meters less than
the length. Find the length and width.
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Perimeter of a rectangle is 2(l+b)
So, as if width is 22 meters less than length, it is l-22 and length is l.
152=2(l-22+l)
= 2(22-2l)
= 44-4l
152+44=4l
196=4l
L=196/4
L=49 then width is l-22 it is 49-22= 27 meters
Hope it helps u
So, as if width is 22 meters less than length, it is l-22 and length is l.
152=2(l-22+l)
= 2(22-2l)
= 44-4l
152+44=4l
196=4l
L=196/4
L=49 then width is l-22 it is 49-22= 27 meters
Hope it helps u
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