Question

the perimeter of a rectangle is 18 3 by 4 metre if the length of the rectangle is twice the breadth find the area of the rectangle

help me.pls​

Answer 1

Answer:

$periemeter => \frac{183}{4} = (l + b)^{2}$

$= > \frac{75}{4}$

$(l + b) = \frac{75}{4}$

$b = x \: \: \: l = 2x$

$2(x + 2x) = \frac{75}{4}$

$2(3x) = \frac{75}{4}$

$6x = \frac{75}{4}$

$x = \frac{75}{4} \times \frac{1}{6}$

$x = \frac{75}{4} \: \:$

$x = \frac{25}{8}$

$l = \frac{25}{8}$

$l = \frac{25}{8} \times 2$

$l = \frac{25}{4}$

Area=

$l \times b$

$\frac{25}{8} \times \frac{25}{4}$

$\frac{625}{32}$