Question

The perimeter of a rectangle is 52 cm where length is 6 cm more than the width of a rectangle . From the pair of linear equations for the above situation and find the dimensions of a rectangle graphically

Answer 1

let the width of the rectangle =x

let the length =x

perimeter =2(l+b)

52=2(6x+x)

52/2=6x+x

26=7x

x=26/7

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Answer 2

Suppose Breadth of rectangle is X

so length will be X + 6

Now Rectangle perimeter = 2(l+b)

52= 2{(X + 6)+X}

52= 2{2X + 6}

52= 4X +12

52-2= 4X

40 = 4X

40/4= X

so, X = 10

So breadth = 10

and length = X + 6

= 10+6

= 16