the perimeter of a rectangle is 76m. the length is two more than twice the width. find the dimensions
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l is length
b is breadth given that l=2b
perimeter=76=2 x[l+b]
=38= 2b +b cancelling 2 and substituting for b
=38=3b
b=12.6666
l=25.3333
b is breadth given that l=2b
perimeter=76=2 x[l+b]
=38= 2b +b cancelling 2 and substituting for b
=38=3b
b=12.6666
l=25.3333
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