Question

the perimeter of a rectangle is 76m. the length is two more than twice the width. find the dimensions

Answer 1

l is length
b is breadth  given that l=2b
perimeter=76=2 x[l+b]
               =38= 2b +b       cancelling 2 and substituting for b
               =38=3b
b=12.6666
l=25.3333