Question

the perimeter of a rectangular feild is 64 m if the length is 20 m find its breadth and area.​

Answer 1

Step-by-step explanation:

Given,

perimeter of a rectangular feild =64 m

length =20m

To find,

breadth and area.

ATQ

now,

let the breadth to be x.

perimeter of rectangle=2(l+b)

64=2(20+x)

64=40+2x

64-40=2x

24=2x

24/2=x

12=x

hence breadth of this rectangular feild is 12m.

now, lets find the area of this rectangular feild.

area of rectangle=l×b

=20×12

=240

hence the area of this rectangular feild is 240m²

Answer 2

‌$\huge \overline{ \underline{\mid \color{red} \tt Answer \color{black}\mid}}$

‌$\blue {\boxed {\boxed {\mathtt {2 \: × \: (Length \: + \: Breadth)}}}}$

‌$\sf\bold{\underline{\underline{\green{Given:-}}}}$

$\circ$ $\mathtt{Perimeter \: = \: 64m}$

$\circ$ $\mathtt{Length \: = \: 20m}$

‌$\sf\bold{\underline{\underline{\green{To \: \: Find:-}}}}$

$\mathtt{Breadth \: = \: ?}$

$\mathtt{Perimeter \: = \: 2 \: × \: (Length \: + \: Breadth)}$

${:}\longrightarrow$ $\mathtt{64 \: = \: 2 \: × \: (20 \: + \: Breadth)}$

${:}\longrightarrow$ $\mathtt{64 \: = \: 40 \: + \: 2 \: × \: Breadth}$

${:}\longrightarrow$ $\mathtt{64 \: - \: 40 \: = \: 2 \: × \: Breadth}$

${:}\longrightarrow$ $\mathtt{24 \: = \: 2 \: × \: Breadth}$

${:}\longrightarrow$ $\mathtt{Breadth \: = \: 24 \: ÷ \: 2}$

${:}\longrightarrow$ $\mathtt{Breadth \: = \: 12}$

‌$\sf\bold{\underline{\underline{\green{Area:-}}}}$

${:}\longrightarrow$ $\mathtt{Length \: × \: Breadth}$

${:}\longrightarrow$ $\mathtt{20 \: m \: × \: 12 \: m}$

${:}\longrightarrow$ $\mathtt{240 \: m²}$

$\mathbb{ BE \: \: BRAINLY }$ ‌$\boxed\checkmark$