when A< 0 determine the nature of roots of the quadratic equation 4x2+x+a=0
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Given : 4x² + x + a = 0
To Find : Nature of roots if a < 0
Solution:
4x² + x + a = 0
D = (1)² - (4)4(a)
=> D = 1 - 16a
a < 0
=> 16a < 0
Multiplying both sides by -ve sign
=> -16a > 0
D = 1 - 16a
=> D > 1
=> D > 0
Hence Roots are real and unequal
if D = 0 , roots equal and real
D > 0 roots real and unequal
D < 0 roots are imaginary
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