Question

The perimeter of a rhombus is 68cm and length of one of its diagonal is 16cm. Find the length of the other diagonal and
area of the rhombus​

Answer 1

Step-by-step explanation:

continue

Substituting the values

17^2=8^2+x^2

289=64+x^2

289-64=x^2

225=x^2

+15 or-15 =x (taking square root)

discarding negative sign

length of the other diagonal DB=2x=2*15 =30cm

hence 30cm answer

thanks

Mark as brainliest

Answer 2

Answer:

AnSwer -:

Length of Diagonal 2 = 8cm

_____________________________

____________________________

Explanation-:

Area of the Rhombus -:

“A = 1/2 x d1 x d2”

A = Area

D1 = Diagonal 1

D2 = Diagonal 2

_____________________________

Given,

Area of Rhombus-: 16 cm^2

Length of Diagonal 1 = 4 cm

To find,

Length of diagonal 2

_______________

Formula of Area of Rhombus-:

Area of the Rhombus -:

“A = 1/2 x d1 x d2”

A = Area = 16 cm^2

D1 = Diagonal 1 = 4 cm

D2 = Diagonal 2 = ??

Then ,

1/2 x 4 x D2 = 16 cm^2

2 x d2 = 16 cm^2

D2 = 16/2

D2 = 8

Hence ,

Length of Diagonal 2 = 8cm

_____________________________

Rhombus-: A Rhombus is a flat shape

with 4 equal straight sides. A rhombus

looks like a diamond. All sides have

equal length.

____________________________

Step-by-step explanation:

mark me as brainliest