Question

the perimeter of a right angle triangle is 140 units and its hypotenuse is 58 units find the length of the Other sides

Answer 1

perimeter=140
x+y+58=140
x+y=82
x=82-y

now according to Pythagoras theorem,
y^2+(82-y)^2=58

find y and put it in equation 1

Answer 2

Answer:

Other sides are 40 and 42.

Step-by-step explanation:

We have been given a right angle triangle:

The perimeter of traingle is:

$x+y+58=140$

$x+y=82$

$y=82-x$

Now, using pythagoras theorem:

$x^2+y^2=hypotenuse^2$

Where, x and y be the other than hypotenuse sides of the right angle triangle.

Substitute $y=82-x$

$x^2+(82-x)^2=58^2$

On simplification we get x= 42 and x=40.

Now, put x=40 in y=82-x

y=82-40=42

When x=42 in y=82-x

y=82-42=40

Hence, the two other sides of triangle are 40 and 42.