Question

The perimeter of a sheet of paper in the shape of a quadrant of a circle is 75 cm. Find its area​

Answer 1

Given,

area of quadrant=75 cm

then,

1/4×2πr=75

1/2×22/7×r=75

r=75×7/22×2

r=47.73 cm

area of quadrant=1/4×π(r×r)

=1/4×22/7×(47.73×47.73)

=1/2×11/7×(2,278.153)

= 1,789.98 sq.cm.

hope its and make me brainliest

Answer 2

Answer:

Given,

area of quadrant=75 cm

then,

1/4×2πr=75

1/2×22/7×r=75

r=75×7/22×2

r=47.73 cm

area of quadrant=1/4×π(r×r)

=1/4×22/7×(47.73×47.73)

=1/2×11/7×(2,278.153)

= 1,789.98 sq.cm.

hope its and make me brainliest