Question

the perimeter of a square is 12 cm and another square is 16 cm. find the perimeter of a square which is equal in area to these combined two squares?

Answer 1

Perimeter of square 1=12cm
a1= side of square 1 = 12/4=3cm
perimeter of square 2 = 16cm
a2=side of square 2 = 16/4=4cm
The sum of the qareas of these two squares = $a1^{2} + a2^{2}$
=$3^{2} + 4^{2}$
=9+16=25$cm^{2}$
the area of the larger square, is therefore,25$cm^{2}$
the side of the larger square=√25=5cm
The perimeter of the larger square=4*5=20cm 
∴The perimeter of the required square is 20cm