the perimeter of a trapezium is 104m, its non parallel sides are 18 m and 22m, and its altitude is 16m. find the area of trapezium.
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S is the area.
We have this formula for an area of trapezium:
S=m\cdot h
Where h is the height and m is mid-segment of trapezium, or:
m=\frac{a+b}{2}
Lets find first a+b.
a+b=104-18-22=64
Therefor \frac{a+b}{2}=\frac{64}{2}=32
S=m\cdot h=32\cdot 16=2^5 \cdot 2^4=2^9=512
We have this formula for an area of trapezium:
S=m\cdot h
Where h is the height and m is mid-segment of trapezium, or:
m=\frac{a+b}{2}
Lets find first a+b.
a+b=104-18-22=64
Therefor \frac{a+b}{2}=\frac{64}{2}=32
S=m\cdot h=32\cdot 16=2^5 \cdot 2^4=2^9=512
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